JAMB 1980
A cell has an open circuit voltage V1 and a closed circuit voltage V2 when a current is flowing through it. Therefore, the internal resistance of the cell is
A. V2/I
B. V1/I
C. (V1+V2)/I
D. (V1−V2)/I
E. (V2−V1)/I
Correct Answer: Option D
Explanation
From the relationship between EMF, Potential difference and the lost voltage we have that
E = V+v
Where E is the open circuit voltage when it is not driving any current to the external circuit
V is the closed circuit voltage the cell is now supplying current to the external circuit
v is the lost voltage
Relating this to the questions, you have
V1 = V2 + v
v = Ir
So, we have;
V1 = V2 + Ir
V1 – V2 = Ir
r = (V1 – V2)/I
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