Jamb 1979
A 500kg car which was initially at rest travelled with an acceleration of 5m/s², its kinetic energy after 4 seconds was A. 10⁵J B. 2.5 x 10³J, C. 2 x 10³J D. 5 x 10³J E. 5 x 10⁵J
ANSWER: Option A
EXPLANATION:
KE = ½mv²
Since v = u + at
KE = ½m(u + at)²
Substitute the values in the equation above to find your answer.
Remember u = 0 as the car started from rest.
Or click here to choose!
Of course, your opinion(s) and suggestion(s) is/are welcome. In case you have any, kindly use our comment box.
If you have any questions, you can also drop them in the comment section.
If you find this post beneficial, feel free to use the share button to share with friends.
Follow us on our Facebook page!
Be the first to comment